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[X^n,P]
[f(x),P] {where f(x) is a function of x}
[d2/dx2,P]
[e^(ax^3),d/dx]
[e^(ax),cos^2bx+sinbx] = 0

2006-10-05 07:06:30 · 2 answers · asked by nathaniel49 2 in Science & Mathematics Mathematics

these are quantum mechanical operators where [ X, P] are operators on a function

2006-10-05 11:32:31 · update #1

2 answers

what is P?
and if you could define [,] more precisely, it would actually help.
what is the operator? is P a function?

well, in that case i would guess the following:
[X^n,P]=P^n
[f(x),P]=f(P)
[d^2/dx^2, P]=d^2 P / dx^2
the last two... i do not know...
sorry

2006-10-07 15:43:02 · answer #1 · answered by Anonymous · 0 0

What is the notation [ , ]? Are they meant to be Poisson brackets? What is P supposed to be?

2006-10-05 17:47:58 · answer #2 · answered by James L 5 · 0 0

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