this h.w needs to be done by monday
2006-10-05 06:48:53 · 7 answers · asked by Chloe S 1 in Education & Reference ➔ Homework Help
√2*3√6*3√3 = 3*3*√2*√6*√3 = 9*√36 = 9*6 = 54
2006-10-05 07:05:03 · answer #1 · answered by Glenn Blaylock 2 · 0⤊ 0⤋
assuming you meant â(2*3)â(6*3)â(3), the answer is 18. Heres why.
Step 1: Rewrite: â6â18â3
Step 2: Simplify: â6*3â2*â3
Step 3: Times the square roots together: â6*3â2*â3 = 3â(6*2*3)
Step 4: Simplify 3â36
Step 5: Take the square root of 36 and times it by 3: 3*6
Step 6: Solve: 18
assuming you meant â(2)*3â(6)*3â(3), the answer is 54. Heres why.
Step 1: Combine outside numerals; In this case, the 3 before â6 and the 3 before â3: 9*â2â6â3
Step 2: Combine Square roots: â2â6â3=â36
Step 3: Solve: 9*â36 = 9*6 = 54
So it can be either 18 or 54 depending on how you write it...
2006-10-05 13:53:06 · answer #2 · answered by CAP 2 · 0⤊ 1⤋
You need to multiply them out two at a time. Any two is fine to start with. When you pick your two expressions, multiply the number outside the first one by the number outside the second one. Then multiply the number under the square root of the first one by the number under the square root of the second one. Once you do that you'll have a new expression with numbers outside and under the square root. Then you need to keep going doing the same with that new number and the third you had left. You should get 9â36 which equals 9*6=54. That's assuming that what you have is (â2 ) * (3â6) * (3â3)
2006-10-05 14:02:47 · answer #3 · answered by gabyrig 3 · 0⤊ 0⤋
The answer is 18.
2006-10-05 13:55:30 · answer #4 · answered by Humberto M 6 · 0⤊ 0⤋
the correct answer is 54
2006-10-05 13:57:52 · answer #5 · answered by roby_chillz 2 · 0⤊ 0⤋
To hell with the answer. How do you make those radicals?
2006-10-05 14:21:03 · answer #6 · answered by Anonymous · 0⤊ 1⤋
sqrt(2)*sqrt(6*9)*sqrt(3*9)
sqrt(2)*sqrt(54)*sqrt(27)
sqrt(54)*sqrt(54)
54
2006-10-05 14:06:37 · answer #7 · answered by okletmeanswer 2 · 0⤊ 0⤋