Jay read somewhere that for a Boeing 747, at least 2 of the engines must be operational for the plane to fly safely. If each engine has a .9999 probability of sucess, what is the probability the plane will go down in a fiery glory?
2006-10-05 06:18:59 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
P(0) = 4C0*(0.9999)^0*(0.0001)^4
= (4!/(4!*0!))*1*(0.0001)^4
= 1E-16
P(1) = (4!/(3!*1!))*(0.9999)^1*(0.0001)^3
= 3.9996E-12
P(0) + P(1) = 3.9997E-12 or 1 in 250,018,751,406.355
over 250 billion to 1
2006-10-05 07:24:06 · answer #1 · answered by T 5 · 0⤊ 0⤋
A boeing 747 has four engines
2006-10-05 13:39:42 · answer #2 · answered by Poor one 6 · 0⤊ 0⤋
How many engines do a Boeing 747 have?
2006-10-05 13:26:44 · answer #3 · answered by Steiner 7 · 0⤊ 0⤋
first of all Boeing 747 has only 2 engines. Is almost imposibile for it go down even if only one engine is operational.
2006-10-05 13:26:37 · answer #4 · answered by yna_2006_cv 1 · 0⤊ 0⤋
one in 9999X9999 or so roughly so something like
1 in 100,000,000
2006-10-05 13:22:55 · answer #5 · answered by kurticus1024 7 · 0⤊ 0⤋
it should be 0.00000001
2006-10-05 13:23:51 · answer #6 · answered by raj 7 · 0⤊ 0⤋