Help Me Show Work.....?

Question

I got the answers, now I need to just show work.....

The ~9.6 mile width of Straits of Gibraltar to kilometers:15.449 702

A 15.2 m tidal range in the Bay of Fundy, Newfoundland to feet:49.868 ft

A 50 gallon drum of crude oil to liters:189.270 L

A 38° F seawater temperature to C°:3.3333333 deg C

A 30 mile per hour wind to meters per second: 13.411 meters/sec

Answer 1

1 mile = 1.609344 ft, so 9.6 miles = 9.6*1.609344

1 meter = 3.280839 ft, so 15.2 miles = 15.2*3.280839 ft

1 gallon = 3.785411 liters, so 50 gallons = 50*3.785411 liters

deg C = 5/9(deg F - 32), so 38 deg F -> 30/9 deg C

30 miles/hr * 1609.344 m/hr * 1 hr/3600 s =
30*1609.344/3600 meters/s

Answer 2

1 mile=1.6 km. so 9.6*1.6

2.1meter=39/12 ft
so 15.2*(39/12)ft

3.1 gallon=3.8 ltre approx
so50*3.8

4.*f to celsius=F-32(5/9)
38-32(5/9)

5.30 mph=48kmph
1kmph=5/18m/s
so 48(5/18)m/s

Answer 3

1 mile=1.6 km. so 9.6(1.6)
2.1meter=39/12 ft
so 15.2(39/12)ft

3.1 gallon=3.8 ltre approx
so 50(3.8)

5.30 mph=48kmph
1kmph=5/18m/s
so 48(5/18)m/s