Hard Math Question, Can you get it???

Question

Let x and y be two numbers whose average is 13 and whose product is 744. Find the value of 2x-3y

Answer 1

well we have x + y = 26 and xy =744. Expressing y in terms of x and substituting, we get x^2 -26x + 744 =0, a second degree equation. Using Bhaskara, we get 2 complex roots so that the numbers are 13 + 5sqrt(23) i and 13 - 5sqrt(23)i, if I didn't make any mistake..

There are no real numbers x and y that satisfy the given conditions.l

Answer 2

a million+a million=2 besides, someone with some distance too a lot time on their fingers keen to teach it... "The evidence starts from the Peano Postulates, which outline the organic numbers N. N is the smallest set gratifying those postulates: P1. a million is in N. P2. If x is in N, then its "successor" x' is in N. P3. there is not any x such that x' = a million. P4. If x isn't a million, then there's a y in N such that y' = x. P5. If S is a subset of N, a million is in S, and the implication (x in S => x' in S) holds, then S = N. then you quite ought to outline addition recursively: Def: enable a and b be in N. If b = a million, then outline a + b = a' (using P1 and P2). If b isn't a million, then enable c' = b, with c in N (using P4), and outline a + b = (a + c)'. then you quite ought to outline 2: Def: 2 = a million' 2 is in N through P1, P2, and the definition of two. Theorem: a million + a million = 2 evidence: Use the first component to the definition of + with a = b = a million. Then a million + a million = a million' = 2 Q.E.D. note: there is yet another formula of the Peano Postulates which replaces a million with 0 in P1, P3, P4, and P5. then you quite ought to modify the definition of addition to this: Def: enable a and b be in N. If b = 0, then outline a + b = a. If b isn't 0, then enable c' = b, with c in N, and outline a + b = (a + c)'. you even ought to outline a million = 0', and 2 = a million'. Then the evidence of the theory above is a touch diverse: evidence: Use the 2d component to the definition of + first: a million + a million = (a million + 0)' Now use the first component to the definition of + on the sum in parentheses: a million + a million = (a million)' = a million' = 2 Q.E.D." Wow, he should be a real hit with the ladies...!! :)

Answer 3

I don't believe that there are two numbers that have an average of 13 and a product of 744.

Answer 4

The average of x and y is 13
(x+y)/2 = 13
x+y = 26 (multiply both sides by 2)

The product of x and y is 744
xy = 744

Use substitution to solve for x and y and then replace x and y in the expression you are given 2x-3y and simplify.

Hope this helps. Good Luck.

Answer 5

x = y / 2 = 13
x + y = 26
x = 26 - y --i
x * y = 744 --ii
using i in ii
26 -y * y = 744
26y - y^2 - 744 = 0
y^2 - 26y -744 = 0
sorry try furthur ur self , an idea is with u just solve it

Answer 6

(x+y)/2=13 => x+y=26 =>x=26-y
xy=744

y*(26-y)=744
26y-y^2=744
y^2-26y+744
are you sure u gave the right numbers?

Answer 7

Since the graphs for the 2 equations never intersect, no two such numbers exist (unless you use imaginary/complex numbers)

Answer 8

[x+y]/2=13...1
xy=744.........2
x+y=26, x=26-y.substitute in ...2
y[26-y]=744
y^2-26y+744=0
y={26+-sqrt[676-2976]}/2
={26+-sqrt[-2300]}/2
=13+-5sqrt-23
x=26-13-+5sqrt-23
=13+-5isqrt23
2x-3y=23+-10sqrt23-39-+15isqrt23
=-16-+5isqrt23

Answer 9

2 points

Answer 10

That's not hard.

(x+y)/2=13
xy=744

Solve for x and y (hint: two variables, two equations)

Then substitute the values of x and y you get into 2x-3y.