c. 34 m
(The base of a rectangle is 10m =LENGTH ,
the height is 7m=breadth.)
Perimeter
=length+breadth+length+breadth
=10+7+10+7
=20+14
=34 m
OR
PERIMETER
=2*length+2*breadth
=2*10+2*7
=20+14
=34m
2006-10-05 04:26:33
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answer #1
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answered by Anonymous
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First perimeter of rectangle was 10 + 10 + 7 + 7 = 34 m
now as sides are halved so 34 / 2 = 17 m
2006-10-05 04:20:56
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answer #2
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answered by pooja 2
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1.perimeter is always expressed in length units.
2.perimeter of the rectangle=(7+10)x2 =34 m
3.if base is haved then the perimeter =(7+5)x2=24 m
4.if height is haved then the perimeter=(3.5+10)x2=26 m
5.if both base & height are haved then the perimeter=(3.5+5)x2=17 m
but in this case new rectangle will appear 1/4 of the original rectangle.
6.to get a correct picture first draw a diagram of a rectangle with base
as 10 cm & height as 7 cm, then modify the diagram as mentioned
in (3), (4) above. you can see for yourself what the picture looks like.
7.if area is what you want then 7x10=70 sq.m. to start with. and you will
find that in (3) & (4) above area is = 35 sq.m. and finally in (5) area is
17.5 sq.m.
hope if this answers your problem and helps you in understanding problem, i am a happy person.
2006-10-05 04:55:56
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answer #3
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answered by charlatan 7
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dilated?
if that means reduced to half the area or instead of 70 m2 to 35 m2 then the circumference comes down from 34 meters to a 3.5 meter high by 10 meter rectangle @ 27 meters. The perimeter.
If dilated means both height and width are reduced to half size, then the perimeter is reduced to half size and the perimeter is 17 meters.
2006-10-05 04:19:56
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answer #4
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answered by Steven A 3
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perimeters are linear measurements, so a & b are out. the perimeter of the original rectangle is 34 m. reduced to 1/2 size, the perimeter is 17 m. answer is d
2006-10-05 07:51:54
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answer #5
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answered by yupchagee 7
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Hi. Add the four new sizes together (5+3.5+5+3.5).
2006-10-05 04:11:02
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answer #6
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answered by Cirric 7
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It is 41m if we dilate its height & 44m if we dilate its base.
So all your options are wrong.
2006-10-05 04:36:50
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answer #7
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answered by syam p 2
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d.17m
2006-10-05 04:11:13
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answer #8
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answered by openpsychy 6
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D
2006-10-05 04:14:13
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answer #9
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answered by java 4
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