how do we solve for the extrema values of?

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how do we solve for the extrema values of?

f(x,y,z)=xyz on x^2 + 2y^2+ 3z^2=6 (hint: the answer is: max=2/sqrt3 and min=-2/sqrt3)

2006-10-05 04:05:20 · 2 answers · asked by Ann T 1 in Science & Mathematics ➔ Mathematics

2 answers

Use Lagrange multipliers

2006-10-05 04:24:33 · answer #1 · answered by Steiner 7 · 0⤊ 0⤋

I'm not going to work through the gory details, but my approach would be to take the partial derivatives of the function, set them all to zero, and start substituting away in the boundary function. If that doesn't do it, I'm stuck.

2006-10-05 04:11:18 · answer #2 · answered by Anonymous · 0⤊ 0⤋