2006-10-05 03:10:25 · 10 answers · asked by arun r 1 in Science & Mathematics ➔ Mathematics
The answer is one.
This can be obtained by applying L'Hospital's rule (because of the indeterminate form 0/0)
The rule states that keep on differentiating the numerator and the denominator (separately) untill an determinate form is obtained
Hence, (d/dx)[Sin(x)] = Cos(x)
Thus taking lim x->0 of [Cos(x)/Cos(x)] we get 1
2006-10-05 04:11:16 · answer #1 · answered by mailfortarun 1 · 0⤊ 1⤋
zero.
sin 0/sin 0
=0/0
=0
2006-10-05 08:48:32 · answer #2 · answered by Anonymous · 0⤊ 0⤋
It's undefined(0/0).
2006-10-05 03:43:02 · answer #3 · answered by steiner1745 7 · 0⤊ 0⤋
sin(0)/sin(0)=1
2006-10-05 03:13:07 · answer #4 · answered by SkkARd 3 · 0⤊ 1⤋
dude go get a friggin' calculator.
it's unknown, because sin(0) is 0.
0/0 is unknown.
2006-10-05 03:12:16 · answer #5 · answered by orangegodvt 1 · 0⤊ 0⤋
sin (0)
2006-10-05 03:11:55 · answer #6 · answered by Crystal 1 · 0⤊ 1⤋
sin(0)/sin(0)=0/0 or indeterminate
use L'Hospital's rule
d sinx/d sinx lim x--->0
cos(x)/cos(x) lim x--->0
cos(o)/cos(o)=1/1=1
2006-10-05 08:07:17 · answer #7 · answered by yupchagee 7 · 0⤊ 1⤋
sin split into sections
2006-10-05 03:12:04 · answer #8 · answered by guyperson1986 1 · 0⤊ 1⤋
Undefined because you can not divide by zero.
2006-10-05 04:07:31 · answer #9 · answered by bruinfan 7 · 0⤊ 0⤋
one
2006-10-05 03:11:43 · answer #10 · answered by Anonymous · 0⤊ 1⤋