please show your solution. tnx.
2006-10-04 19:19:47 · 7 answers · asked by chalkey 1 in Science & Mathematics ➔ Mathematics
The slope = y'= 2x+3
integrtating y = x^2+3x + c where c is a constant
passes through 1,6
so 6 = 1+3+c =>c = 2
so y = x^2+3x+2 is the curve
2006-10-04 19:24:05 · answer #1 · answered by Mein Hoon Na 7 · 4⤊ 0⤋
f(x)=2(1)+3=5
2006-10-05 02:23:39 · answer #2 · answered by Richard H 2 · 0⤊ 1⤋
f(x) = integral(2x+3)dx = x^2+3x+C
6 = 1+3+C
C = 2
f(x) = x^2 + 3x + 2
2006-10-05 04:18:41 · answer #3 · answered by Helmut 7 · 0⤊ 0⤋
f(x) = x2 + 3x + 2
slope of 2x + 3 means the gradient is 2x + 3 = f'(x)
Therefore, integrate f'(x) = 2x + 3 to get
f(x) = x2 + 3x + c
to find c, substitute (1,6) into it
2006-10-05 02:25:34 · answer #4 · answered by band_craze4f 3 · 0⤊ 0⤋
when x=1, slope = 5
ans : y-6 = 5(x-1)
y=5x-5+6
thus f(x) = 5x+1
2006-10-05 02:24:27 · answer #5 · answered by NeedHelpGivesHelp 2 · 0⤊ 0⤋
f'(x)=2x+3
f(x)=integral(2x+3)=x^2+3x+c
f(1)=6=1^2+3*1+c
6=4+c
c=2
f(x)=x^2+3x+2
2006-10-05 03:12:23 · answer #6 · answered by yupchagee 7 · 0⤊ 0⤋
do you go to itt tech?
2006-10-05 02:22:31 · answer #7 · answered by Anonymous · 0⤊ 1⤋