help me with this java code?

Question

what's wrong with this java code:

if (number.indexOf("111") == -1)
threeConsecutive = false;
else
threeConsecutive = true;

I have 111 on my number but why does it still return to false, what's wrong?

Answer 1

i tried your program and it works ok

class Np{
public static void main(String arg[]){
boolean threeConsecutive;
String number="000111222333444";
System.out.println(number.indexOf("11"));
if (number.indexOf("11")==-1){
threeConsecutive = false;
}
else
{threeConsecutive = true;
}System.out.println(threeConsecutive);
}
}
>java -cp ./:$CLASSPATH Np
3
true

better use
(number.indexOf("111")==-1)?false:true)
may be a bug with your jvm version.

Answer 2

Do you stop the loop you are in when checking the next three characters? If so, the next loop around will change threeConsecutive to false, and at the end it will be false.

If there are 3 consecutive 1s, it would be best to stop the loop then. If this is not the case, then it may be the old if else else problem, so you may need to place the brackets around your code { }.

Answer 3

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Answer 4

if number is a string, you have to use .compareTo to determine equality. == will determine if they share the same memory which is not what you want most likely.

Answer 5

{ proper semicolons? }

Answer 6

two equal signs?