ok, i asked something similar earlier...and people answered that to find your velocity you do d/t which is fine, but in this case i'm not throwins straight and theres a bunch more involved so....
Heres the deal: I have:
Dx= 5.45m
t=1.97s
Vx = 2.76 m/s
Vf= 0 m/s
a=g
Now...how do I find either V or Vy to get the missing side and calculate how fast i throw in mph?
I honestly can't figure this out...please help
2006-10-04 15:30:39 · 3 answers · asked by tripp 1 in Science & Mathematics ➔ Physics
What is this?
An object at rest is accelerated during 1.97 seconds. At the end of the 1.97 seconds it is travelling at 2.76 meters/second and has traveled 5.45 meters?
2006-10-04 15:38:36 · answer #1 · answered by ? 6 · 0⤊ 0⤋
its all a remember of how a concepts you're going, in case you're going below a mile it is going to appear as if there is not any huge difference in time (to boot the way it feels) in case you're going 20 miles it is going to take you a million hour, yet in case you're going 40 mile it is going to in worry-free words take you 1/2-hour. in short, convinced 40 mph is faster than 20 mph
2016-10-16 03:35:36 · answer #2 · answered by ? 4 · 0⤊ 0⤋
use the x(t) equation.
convert m/s to mi/hour:
A m/s * 60 sec/min * 60 min / hr * X ft / m * Y mi/ft = 3600*X*Y*A mph.
I don't have X and Y offhand.
2006-10-04 15:39:25 · answer #3 · answered by bequalming 5 · 0⤊ 0⤋