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4 answers

Try this method:

let u = x^2

The new expression (in terms of u) is: u^2 - 13u + 36 = 0
factoring the above expression, you get:
(u-9)(u-4) = 0

recall u = x^2, so

(x^2-9)(x^2-4) = 0
(x+3)(x-3)(x+2)(x-2) = 0

Good luck.

2006-10-04 15:04:27 · answer #1 · answered by alrivera_1 4 · 0 0

if i am correct this is what you get

x^4 - 13x^2+ 36
x^2( x^2-13+36)
X^2(x^2+23)

that is as far as you can go

2006-10-04 22:25:37 · answer #2 · answered by !@#$$ 2 · 0 0

(x-3)(x-2)(x+2)(x+3)

2006-10-04 22:05:18 · answer #3 · answered by James A 2 · 0 0

use the quad equation it should be easy

2006-10-04 22:01:45 · answer #4 · answered by Anonymous · 0 0

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