Can anyone help me determine these masses and figure this out? My experiment was formation of magnesium oxide.

Question

I formed Magnesium oxide from magnesium metal. Here is the following data:
1) Mass of crucible and cover= 32.032g
2) Mass of crucible, cover and magnesium= 32.346g
3) Mass of crucible, cover and oxide after 1st heating= 32.556g
4) Mass of crucible, cover and oxide after 2nd heating= 32.559g

Can anyone tell me how to find the following:
1) Mass of magnesium metal
2) mass of magnesium oxide
3) Mass of oxygen in the magnesium oxid
4) Moles of magnesium in the sample
5) Moles of oxygen in the sample
6)experimental ration of mol Mg to one mol 0 (decimal form)

More questions:

6) experimental ratio of mol Mg to one mol O (decimal form)
7) Simplest interger ratio of Mg to O ( from #6 above)
8) Empirical formula from data
9) % magnesium in the oxide from data

Answer 1

Well, first off, your weight after the second heating should not have gone up, but instead should have dropped.

1) Mass of magnesium metal = Weight 2 - Weight 1
2) Mass of magnesium oxide = Weight 4 - Weight 1
3) Mass of oxygen = Weight 4 - Weight 2
4) Moles of magnesium = Answer 1 / 24.31
5) Moles of oxygen = Answer 3 / 16.00 (not 32, which is O2)
6) Ratio = Answer 4 / Answer 5

Answer 2

1) Mass of magnesium metal would be #1 subtracted from #2
2) mass of magnesium oxide would be #4 minus #1
For the next few questions you need to have the formula for magnesium oxide which i believe is MgO
3) Its a long proccess but you get the mass of MgO .539 multiply that by (1 mol of MgO/46.3 g MgO) then mutiply that by the mole to mole ratio which is (1 mol of O/ 1 mole of MgO) then by the mass of O in grams per 1 mol so (16.0 g of O/ 1 mole of 0) you get .186 grams
This is getting really long and I have homework of my own. I hoped I helped you out some.