how would i factor x^3 - 12x^2 + 35x ??

Answer 1

Always begin a factoring problem by factoring the greatest common factor (GCF) from all terms, assuming the GCF is other than 1. In this case, it is x:

x(x^2 - 12x + 35)

Now, try to factor the trinomial. Since the coefficient of x^2 is 1 (the nicest type!), then all you need to look for are two numbers whose SUM is -12 and whose product is 35. Answer: -5 and -7. Use this to factor the trinomial:

x(x - 5)(x - 7), which is the answer to the problem.

Answer 2

First factor out an x. So you have: x(x^2 - 12x + 35)
Now factor the inside. What two numbers add to -12 and multiply to 35? -5 and -7, of course. So now you have x(x - 5)(x - 7). Done!

Answer 3

you want to get it into the form of x^2 +x + (a number), so,

x (x^2-12x+35) because when you multiply exponents, you add them, so x(x^2) would be x^3 because x^1(x^2)

so now you can turn x^2-12x+35 into the form such as (x+2)(x-4) in which you multiply the two numbers to get the end number in the orig. equation, and add them together to get the middle number in the orig. equation, so

the answer would be:
(x-7)(x-5) because you multiply -7 and -5 to get a positive 35, and add them together to get -12. Hope that helps....

Answer 4

Lets see here, first take out the x to get
x(x^2 -12x + 35)

we need to find two number whose sum is -12 and whose product is 35. Do you know why, if not find out.

that would be -7 and -5
x[(x - 7)(x-5)]

Answer 5

x(x^2-12x+35)
x(x-5)(x-7)

First divide by "x", then factor x^2-12x+35

Answer 6

x ( x^2 -12 x + 35)

x [ (x-7) ( x-5 )]

Answer 7

x(x^2-12x+35)
(x)(x-7)(x-5)

Answer 8

=x(x^2-12X+35)
=x(x^2-5x-7x+35)
=x(x(x-5)-7(x-5))
=x(x-7)(x-5)