0 = (x+5)(x+5) -6
0 = x^2 + 5x +5x + 25 - 6
0 = x^2 + 10x + 19
You then need to use the quadratice equation and solve for x.
2006-10-04 14:31:56
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answer #1
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answered by Anonymous
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As others have pointed out this eqquation resolves to x^2 + 10x + 19=0. As the discriminate is not a perfect square, it cannot be resolved into rational factors.
2006-10-05 04:51:55
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answer #2
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answered by A S 4
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(x+5)(x+5)-6=0
Use FOIL
x^2+5x+5x+25-6=0
Combine Like Terms
x^2+10x+19=0
Use quadractic formula.
x=(-10屉(100-4*19*1))/2*10
x=(-10屉24)/20
x=(-10±2â6)/20
x=(-5屉6)/10
2006-10-04 21:48:21
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answer #3
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answered by Jess 2
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(x+5)^2=6
expand the brackets
x^2+10X+25=6
x^2+10x+19
I hope thats what you mean by factor, its about all you can do with it. Hav fun!
2006-10-04 21:36:59
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answer #4
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answered by queen_chelley 1
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i think this might be right
i am winging it here
0= (x+5)^2-6
0= (x=5)(x=5)-6
0= (x^2+5x+5x+25-6)
0= (x^2+10x+21)
0= (x+7)(x-3)
2006-10-04 21:35:20
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answer #5
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answered by !@#$$ 2
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(x+5)(x+5)-6=0
x^+10x+25-6=0
x^+10x+19=0
^ means squared and I assume you put the 2 after "^" to mean squared.
2006-10-04 21:37:40
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answer #6
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answered by Mitchell B 4
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First multiply (x+5)(x+5), then I'm sure you could get on from there.
2006-10-04 21:30:34
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answer #7
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answered by Psycho Dork 2
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