How do you solve this? (x-10)(x-2)= -20?

Answer 1

(x - 10)(x - 2) = -20
x^2 - 2x - 10x + 20 = -20
x^2 - 12x + 20 = -20
x^2 - 12x + 40 = 0

x = (-b ± sqrt(b^2 - 4ac))/(2a)

x = (-(-12) ± sqrt((-12)^2 - 4(1)(40)))/(2(1))
x = (12 ± sqrt(144 - 160))/2
x = (12 ± sqrt(-16))/2
x = (-12 ± 4i)/2
x = -6 ± 2i

ANS : x = -6 + 2i or -6 - 2i

Answer 2

x/10 = (x-2)/20

Answer 3

(x -10) (x - 2) = -20 ( multiply factors together)

x^2 - 12x -20 = -20

x^2 -12x -20 +20 = 0

x^2 - 12x = 0

x(x -12) = 0

x=0

x-12 =0 => x= 12
answer: 0 12

Answer 4

FOIL (x-10)(x-2)
Multiply first x&x
Then multiply x&2
Multiply 10&x
Multiply 10 & 2
x^2+10x+2x+20
or x^2+12X+20

Then, use the quadratic formula.
x=-b+the square root of b^2-4ac, then divide by 2a

Anything to the second power is a.
One X=b
integer=c

So a=1
b=12
c=20

So, just plug in the numbers into the formula

Answer 5

(x-10)(x-2)=-20
x^2-12x+20=-20
x^2-12x+40=0

using the quadratic equation to solve:
x = 6 + 2i or x = 6 - 2i