2006-10-04 14:08:07 · 5 answers · asked by yagermon_10 1 in Education & Reference ➔ Homework Help
(x-2y+3)(x + 2y - 3)
you need to recognize it as a difference of square prob and
build it up like that.
difference of squares:
you need to recognize that to get an x^2 item and a y^2 WITHOUT an xy item that is the difference of squares.
(x+y)(x-y) but you have 4ys... so the multipler has got to be 2 fo r y:
(x+2y)(x-2y) you have a constant of 9 which is 3^2 therefore:
(x+2y+3)(x-2y-3) corrected from the previous
2006-10-04 14:13:05 · answer #1 · answered by want2no 5 · 0⤊ 0⤋
you have a difference of two squares: x^2 and (4y^2 - 12y -9). factor (4y^2 - 12y - 9). think of the whole equation as x^2 - y^2. this factors out to (x - y)(x + y). substitute x^2 into the x part of the equation and substitute the factored part of (4y^2 - 12y - 9) in to the y part.
2006-10-04 21:20:05 · answer #2 · answered by Anonymous · 0⤊ 0⤋
group the first 2 and last 2
(x^2 - 4y^2) + (-12y - 9 )
factor
(x - 2y)(x + 2y) - 3(4y + 3)
2006-10-04 21:14:28 · answer #3 · answered by jxjub 2 · 0⤊ 0⤋
what math class is this for? i remember doing that stuff, but it was so long ago... somehow you have to create a different equation. and put all your ys on one side of the equal sign and your xs on the other... x^2 = -4y^2 - 12y +9 that's all i remember now... sorry... is this algebra? or algebra 2?
2006-10-04 21:13:38 · answer #4 · answered by Curious Blair 3 · 0⤊ 0⤋
factor out the y and the coeffients ( -4y)
that leaves you with -4y(x^2+y+3-9)
substract whole numbers (3-9) which leaves you with -6
-4y(x^2+y-6)
2006-10-04 21:29:04 · answer #5 · answered by !@#$$ 2 · 0⤊ 0⤋