how do you solve 2+4x=19x-13?

Answer 1

2+4x=19x-13
2+13=19x-4x
15 = 15x
1 = x
x = 1

Answer 2

subtract 4x from 19x and that should leave u with 2=15x-13, then add 13 to 2 and you should have 15=15x, Last divide 15 by 15 and u should get 1 so there for 1=x

Answer 3

2+4x=19x-13
-4x -4x
2 =15x-13
+13 +13
15=15x divide both sides by 15
x=1

Answer 4

First thing to do is the easy stuff. Subtract 2 from both sides of the equation. That leaves you with:

4x = 19x - 15

Then, get the variables on the same side of the equals sign. Subtract 4x from both sides of the equation. That leaves you with:

0 = 15x - 15

Then, get the constants on the same side of the equals sign. Add 15 to both sides of the equation. That leaves you with:

15 = 15x

The last thing to do is divide both sides of the equation by 15. That leaves you with:

1 = x (which the Law of Identity allows you to translate into "x=1").

Answer 5

ok first u have to transpose the 4x to the other side to make it 2=19x-4x-13 then transpose the -13 to the other side to make it 2+13=19x-4x then you simplify to make it 15=15x then divide both sides by 15 to make x=1

Answer 6

x=1
2+4x=19x-13
subtract 2 from each side
4x=19x-15
subtract 19x from each side
15x=15
divide above by 15
answer is 1

Answer 7

2+4x = 19x - 13
15=15x
x=1

Answer 8

2+4x=19x-13 add-4x to each side

2=15x-13 add+13 to each side

15=15x divide each side by 15

1=x

Answer 9

2+4x=19x-13
2+13=19x-4x
15=15x
15/15=15x/15
1=x
x=1

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Answer 10

2+4x=19x-13
4x-19x=-13-2
-15x=-15
x=1