2006-10-04 13:49:51 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
∫sin² x dx = ½ x − ¼ sin 2x + C
2006-10-04 13:59:33 · answer #1 · answered by engineer01 5 · 15⤊ 51⤋
Integral Of Sin 2x
2016-10-06 00:24:05 · answer #2 · answered by mauzon 4 · 0⤊ 0⤋
SINCE,cos2x=1-2(sinx)^2
(sinx)^2=(1-cos2x)/2
so we can integrate (1-cos2x)/2....
integrating...
1/2 you can take it outside the integral sign as it is constant...
Integrate "1" and "cos2x" independently..
integration of 1 with respect to x is = "x"
integration of cos2x with respect to x is ="(sin2x)/2"
so the answer is =1/2[x-(sin2x/2)]+c
2006-10-04 17:48:59 · answer #3 · answered by Anonymous · 21⤊ 1⤋
I've made a beautiful video on this 😊😊
https://youtu.be/Twc1Rv6E2-c
2016-04-23 21:37:59 · answer #4 · answered by Yacine 1 · 0⤊ 0⤋
https://www.youtube.com/watch?v=FipVgpgHykY
2014-08-31 11:19:35 · answer #5 · answered by ? 1 · 0⤊ 0⤋
sinx^2
2014-11-14 18:57:15 · answer #6 · answered by Anonymous · 0⤊ 7⤋
(sin(x))^2 =(0.5-0.5cos(2x))
int{(sinx)^2} = int{0.5 - 0.5cos2x}
= 0.5x -0.25sin2x
2006-10-07 05:02:01 · answer #7 · answered by purushotham s 1 · 3⤊ 3⤋
Since cos(2x)=1-2(sin(x))^2, then (sin(x))^2=(1-cos(2x))/2, from that you get that
integral[(sin(x))^2] = integral[(1-cos(2x))/2] = x/2 - sin(2x)/4 + c
where c is a constant.
I hope this helps.
2006-10-04 14:07:40 · answer #8 · answered by karlterzaghi 2 · 71⤊ 0⤋
Please take a look at the beautifully typed PDF below. Each step is annotated, and it looks as it would in a book. http://www.tomsmath.com/step-by-step-instructions-for-finding-the-antiderivative-of-sine-squared-of-x.html
2014-06-04 10:45:12 · answer #9 · answered by ? 3 · 0⤊ 7⤋
sin^2(90)=x
2014-05-23 08:22:29 · answer #10 · answered by ..!!*~*!!.. 1 · 0⤊ 17⤋