It's hard can u help?!?

Question

Everyone,

This is the equation: 3 to the 3rd power/[6 to the 2nd power-(16+8)]
I know what the answer is, but I need someone to show me the way to solve it. Set it up for me please

Answer 1

3^3/[6^2-(16+8)]
=3^3/[6^2-(24)]
=3^3/[36-24]
=3^3/[12]
=27/12
=2.25

Answer 2

The way to answer this is to remember the order of precedence for performing the individual component equations in your larger equation.

Do the exponents first. (3^3 = 27) and (6^2 = 36)

That leaves you with the following equation:

27/(36 - (16+8))

Do the inside-most parentheses next. (16+8 = 24)

That leaves you with the following equation:

27/(36-24)

Do the parentheses next. (36-24 = 12)

That leaves you with the following equation:

27/12

Do the division next. (27/12 = 2.25 or, written as a fraction, 2-1/4)

So the answer is two and one-fourth.

Answer 3

3 to the third power is 3x3x3 = 27
6 to the second power is 36; (16+8) is 24; 36 - 24 is 12

So you have 27/12 which reduces to 9/4

Answer 4

Equation:3^3/[6^2-(16+8)]
=27/[36-24]
=27/12
27/3=9 and 12/3=4
The answer is 9/4

If you divide it it's going to be: 2 and 1/4 or 2.25

Answer 5

if the equation like this ... 3^3/[6^2-(16+8)] then it goes like this:
3^3=27,
6^2=36
the equation would be : 27/[36-(16+8)]=27/[36-24]=27/12=2.25

i hope its correct and helpful

Answer 6

3x3=9[6x6=36-(16+8)]= 9(36-24)= 9(12)=108

Answer 7

27/[36-24]
27/12
but i can't see a whole number out of that.

Answer 8

3^3/[6^2-(16+8)]

3^3/[6^2-(24)]

3^3/[36-24]

3^3/[12]

27/12

=2.25

Answer 9

ask yahoo answers they can answer it for u

Answer 10

you should have paid more attntion in class