Can you also show work and explain how you got the answer thanks!
A helicopter is ascending vertically with a speed of 6.00 m/s. At a height of 195 m above the Earth, a package is dropped from a window. How much time does it take for the package to reach the ground?
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2006-10-04 13:23:01 · 4 answers · asked by beast 1 in Science & Mathematics ➔ Physics
X = V * t + 0.5 * a * t^2
195 m = -6 m/s * t + (0.5)*(9.8 m/s^2) * t^2
Solve for t.
I get 6.95 seconds.
2006-10-04 13:49:27 · answer #1 · answered by The Terminator 2 · 0⤊ 1⤋
listed below are the equations: a = consistent = -9.8 m/s² (continually) V = Vo + a*t Y = Yo + Vo*t + ½*a*t² (time-honored as 'function' in the question) Vo is +9.8 m/s and Yo is 0 on the superb of the construction. placed the time values into the above equations and fill in the chart. The recommendations to the two ?s below it will become obtrusive. the superb of the flight is jointly as V = 0 and the roof point implies Y = 0
2016-10-18 12:23:58 · answer #2 · answered by ? 4 · 0⤊ 0⤋
the answer which u have got is not right as the plane is ascending vertically
so the package will not go immediately downwards it will follow the path of a parabola
2006-10-05 06:14:58 · answer #3 · answered by ash007 2 · 0⤊ 0⤋
Standard formulation is
x(t) = 0.5*g*t^2 + v0*t + x0
g = -9.8 m/s/s
v0 = 6 m/s
x0 = 195 m
x(t) = 0
0 = -4.9*t*t + 6*t + 195
t = 6.95 s
2006-10-04 13:53:46 · answer #4 · answered by feanor 7 · 0⤊ 0⤋