ok....... how do you solve: 8x+4y=6
4x=3-y ....???.........(the 8x+4 one is over the 4x =3 one..... substution method i think....but i dunno?)
2006-10-04 13:21:56 · 8 answers · asked by Anonymous in Education & Reference ➔ Homework Help
ok on the 2nd equation you solve for y. then you plug that into 8x+4y=6 like these: 8x+4(3+4x)=6 solve for x than plug that number to solve for y.
GOOD LUCK!!!!
2006-10-04 13:33:42 · answer #1 · answered by beary 1 · 0⤊ 0⤋
Ok lets think
8x+4y=6
-4 -4
8x/4 = 6-4 6-4= 2
so, 8 times what divided by four =2
so, x=1 cuze 8 times 1 = 8 divided by 4 =2
so 1 + 4y= 6
think what times four divided by 2= 6
3 so y= 3 and x= 1
2006-10-04 13:35:39 · answer #2 · answered by answers35793 1 · 0⤊ 0⤋
If you want to do it by substitution, add y to both sides of the second equation then subtracy 4x from both sides to get y = 3 - 4x. Then replace the y in the other equation with (3-4x) to get:
8x + 4(3 - 4x) = 6
Distribute the 4: 8x + 12 - 16x = 6
Simplify: -8x + 12 = 6
Subtract 12 from both sides then divide both sides by -8 to get x = -6/-8 or 3/4
Plug this in to x in one of the eauations and find y:
4(3/4) = 3 - y
3 = 3 - y
0 = y
2006-10-04 13:30:37 · answer #3 · answered by hayharbr 7 · 0⤊ 0⤋
make one of them be like this: y=3-4x (the second equation) then stick it in where the y is on the first, so: 8x+4(3-4x)=6 see how i stuck y=3-4x into the second one where y was? Then you solve for x:
8x+12-16x=6
12-8x=6
-8x=-6
x=3/4
Then plug x=3/4 into the second equation:
4(3/4)=3-y
12/4=3-y
3=3-y
3-3=-y
0=y
2006-10-04 13:36:29 · answer #4 · answered by Bo Jangles 2 · 0⤊ 0⤋
Sure, we can do substitution:
4x=3-y
y=3-4x
Plug this into the second equation:
8x+4(3-4x)=6
8x+12-16x
-8x=-6
x=3/4
Plug this into the first equation:
y=3-4(3/4)
y=0
Thus your solution is (x, y) = (3/4, 0)
2006-10-04 13:27:52 · answer #5 · answered by Pascal 7 · 0⤊ 0⤋
8x+4y=6
4x=3-y
take 4x=3-y divide by 4 x=3/4-y/4
then substitute it into 8x+4y=6
8(3/4-y/4)+4y=6
(24/4-8y/4)+4y=6
6-2y+4y=6
6+2y=6
2y=0
y=0
8x+4(0)=6
8x+0=6
x=6/8 or x=3/4
2006-10-04 13:36:25 · answer #6 · answered by creative_idea_thinker 2 · 0⤊ 0⤋
8x+4y=6 4x=3-0
4x=3-y 4x=3
2(3-y)+4y=6 /4 /4
6-2y+4y=6 x=3/4
6+2y=6
-6 -6
________
2y=0
/2 /2
_____
y=0
solution (3/4,0) x=3/4 and y=0
2006-10-04 13:28:29 · answer #7 · answered by ... 6 · 0⤊ 0⤋
4 (x-2) (x+5) i gets it, no I won't, chemist did, no, 18 and 11? come on C: 5 x^6 (x+2) (x+9) yet thank you for beginning it! 3 (x^2+y+15xy-11) (it style of feels like I;m lacking something) -(q-6) (q-a million)
2016-12-26 09:57:58 · answer #8 · answered by ? 3 · 0⤊ 0⤋