2x^2+10x+11=0
I came up with 5+/-sqrt3 over 2
Anyone else?
2006-10-04 13:19:12 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
I don't think you can use completing the square on that one, 11 is not evenly divisible by 2
2006-10-04 13:25:59 · answer #1 · answered by CHAZ2006 3 · 0⤊ 0⤋
2x^2+10x +11
pull two out as gcf
2(x^2+5x+11/2)=0
take 1/2 of 5x term and add and subtract (don't forget to multiply the 2.5 term by the 2 outside when you added it in addition to squaring it) 2.5^2 *2
2(x^2+5x+2.5-2.5)=-11/2+2.5^2*2
2(X+2.5)^2-1.5=0
2006-10-04 20:45:18 · answer #2 · answered by James_Solo501st 1 · 0⤊ 0⤋
This is what happens
2x^2+10x+11=0
2(x^2+10x+11)=0
2(x+?/?)( x- ?/?) Your points will be fractions and not whole numbers.
2006-10-04 20:27:56 · answer #3 · answered by !@#$$ 2 · 0⤊ 0⤋
2x^2 + 10x + 11 = 0
2x^2 + 10x = -11
x^2 + 5x = (-11/2)
x^2 + 5x + (25/4) = (3/4)
(x + (5/2))^2 = (3/4)
x + (5/2) = sqrt(3/4)
x + (5/2) = (1/2)sqrt(3)
x = (-5/2) ± (1/2)sqrt(3)
x = (1/2)(-5 ± sqrt(3))
So you are correct.
2006-10-04 22:58:09 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋