What is the time lapse between seeing a lightening strike and hearing the thunder if the lightening flash is 4km away?
2006-10-04 13:09:58 · 4 answers · asked by JJ L 1 in Science & Mathematics ➔ Other - Science
This is pretty easy.
4 km /(300,000 km/sec) = 0.0000133 s
4 km / (0.333 km/sec) = 12.01 s
The lag is 12.01s -0.0000133s or 12 seconds.
2006-10-04 13:17:13 · answer #1 · answered by Wicked Mickey 4 · 0⤊ 0⤋
As you're close, as quickly as you spot the lghtening initiate counting the seconds until you pay attention the thunder. the speed of sound is around 350 m/sec so in case you count quantity 6 seconds the area to the flash is 2100 meters of a million.25 miles or so.
2016-10-18 12:22:57 · answer #2 · answered by ? 4 · 0⤊ 0⤋
4 km=4,000 meters. Divide 4,000 by 333 and you get 12.01 seconds. For a distance of only 4,000 meters, you could assume no delay on sighting the flash. So your answer would be 12. seconds. If your teachers insist on "ridiculous" accuracy, divide 3x10(to the 8th power) by 4,000. and you get .0000133 second delay on seeing the lightning.
2006-10-04 13:39:56 · answer #3 · answered by Scoop81 3 · 0⤊ 0⤋
c = speed of light, 3x10^8 m/sec
l = speed of sound, 3.33x10^2 m/sec
Distance = 4 km = 4x10^3 meters
Time for light to travel: c/distance = (4x10^3)/(3x10^8) sec
= 1.33x10^-5 sec, or 0.0000133 seconds
Time for sound to travel: l/distance = (4x10^3)/(3.33x10^2) sec
= 1.2012012^10 = 12.012 seconds
Difference = 12.012012- 0.000013 = 12.011999 seconds
2006-10-04 13:24:10 · answer #4 · answered by Tom-SJ 6 · 0⤊ 0⤋