what is the answer to n(n-1)+(n-1)n+n(n-1)over 2?

0 ⤊

I have a common fraction and need the answer. n(n-1)+(n-1)n+n(n-1) all over 2

2006-10-04 12:55:00 · 4 answers · asked by Lorrie W 1 in Education & Reference ➔ Homework Help

Solve the parentheses first:
n(n-1) = n^2-n

SO
[n^2-n + n-1 + n^2-n]/2 = [2n^2 - n - 1]/2

2006-10-04 12:58:36 · answer #1 · answered by LadyJag 5 · 0⤊ 1⤋

{n(n-1)+n(n-1)+n(n-1)} /2
combine n(n-1) + n(n-1) +n(n-1) = 3n(n-1)
therefore
3n(n-1)/2 or 3/2 n(n-1)

2006-10-04 20:09:18 · answer #2 · answered by captn_carrot 5 · 0⤊ 0⤋

3n(n-1)/2

2006-10-04 19:57:17 · answer #3 · answered by Pascal 7 · 0⤊ 1⤋

I dunno, but it probably has an n in it

2006-10-04 19:58:54 · answer #4 · answered by Anonymous · 0⤊ 1⤋