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what is the intersection point in the graph of the lines

8x-3y= -3 and 4x-2y= -4

2006-10-04 12:40:42 · 4 answers · asked by someguy 2 in Science & Mathematics Mathematics

4 answers

Hey, you asked a question like this already! I gave you all the details of how to do it yourself... perhaps you should try this and we can check *your* answer. :-)

8x - 3y = -3
4x -2y = -4

Double the second equation:
8x - 3y = -3
8x - 4y = -8

Subtract the second from the first:
y = 5

Now substitute y into one of the equations and solve for x:
8x - 3(5) = -3
8x - 15 = -3
8x = 12
x = 1½

So the point of intersection is (1½, 5)

Double check with the other equation:
4(1½) - 2(5) =? -4
6 - 10 =? -4
-4 = -4 <--- check

So the point of intersection is definitely (1½, 5)

P.S. I won't answer the next one for you, though

2006-10-04 12:50:04 · answer #1 · answered by Puzzling 7 · 1 0

First multiply the first equation by 2 and the second by -3 and then add them.

2(8x-3y=-3) = 16x-6y=-6
-3(4x-2y=-4) = -12x+6y=12
------------------ ---------------
4x = 6
Divide both sides by 4
x = 1.5

Then insert this x value in one of the original equations and solve for y.

4(1.5)-2y=-4
6 - 2y=-4
Add 4 to both sides
10 - 2y = 0
Add 2 y to both sides
10=2y
Divide by 2
5 = y

This is your intersection point

(1.5, 5)

2006-10-04 19:53:34 · answer #2 · answered by danjlil_43515 4 · 0 0

8X-3Y=-3
4X-2Y=-4

x bottom by -2 and add

Y=5

4X = 2Y -4 4X= 6 x=3/2

2006-10-04 19:51:15 · answer #3 · answered by rwbblb46 4 · 0 0

x=(3y-3)/8 and x=(2y-4)/4
3y-3=4y-8
8-3=y=5
x=12/8=1.5
x=6/4=1.5

2006-10-04 19:49:34 · answer #4 · answered by Don't look too close! 4 · 0 0

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