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anyone know?

2006-10-04 12:26:08 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

6 answers

C(30,2) = "30 choose 2"
= 30! / (30-2)! 2!
= 30! / 28! 2
= 30 x 29 / 2

Here's a simple way to think of it:

There are 30 choices for the first person to include in the conversation and 29 for the second person. This would be 30 x 29, but the order doesn't matter (if I pick Anne first and then Bob, it's the same as picking Bob first and then Anne). It's just one pairing of people. So divide by 2.

( 30 x 29 ) / 2 = 435 conversations

2006-10-04 12:27:22 · answer #1 · answered by Puzzling 7 · 1 0

Question is how many pairs of people are possible from a group of 30. Each of the 30 has a choice of 29 with whom to talk or30*29=870. this has to be divided by 2 since person a talking to person c is the same as person c talking to person a etc.
Answer is 29*30/2=435.

2006-10-08 17:02:39 · answer #2 · answered by yupchagee 7 · 0 0

435
because 30 people means 15 two people conversations and one person can have conversation with 29 other people
therefore
15 x 29 = 435 converstaions

2006-10-04 19:55:27 · answer #3 · answered by Fatima A 3 · 0 0

2^30 converstaions

2006-10-04 19:33:53 · answer #4 · answered by LeBlanc 6 · 0 0

435 - add up 29+28+27+....+2+1

2006-10-04 19:29:35 · answer #5 · answered by J 3 · 0 0

if you can talk to only one person at a time, then the answer is 15

2006-10-04 19:32:54 · answer #6 · answered by Anonymous · 0 0

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