C(30,2) = "30 choose 2"
= 30! / (30-2)! 2!
= 30! / 28! 2
= 30 x 29 / 2
Here's a simple way to think of it:
There are 30 choices for the first person to include in the conversation and 29 for the second person. This would be 30 x 29, but the order doesn't matter (if I pick Anne first and then Bob, it's the same as picking Bob first and then Anne). It's just one pairing of people. So divide by 2.
( 30 x 29 ) / 2 = 435 conversations
2006-10-04 12:27:22
·
answer #1
·
answered by Puzzling 7
·
1⤊
0⤋
Question is how many pairs of people are possible from a group of 30. Each of the 30 has a choice of 29 with whom to talk or30*29=870. this has to be divided by 2 since person a talking to person c is the same as person c talking to person a etc.
Answer is 29*30/2=435.
2006-10-08 17:02:39
·
answer #2
·
answered by yupchagee 7
·
0⤊
0⤋
435
because 30 people means 15 two people conversations and one person can have conversation with 29 other people
therefore
15 x 29 = 435 converstaions
2006-10-04 19:55:27
·
answer #3
·
answered by Fatima A 3
·
0⤊
0⤋
2^30 converstaions
2006-10-04 19:33:53
·
answer #4
·
answered by LeBlanc 6
·
0⤊
0⤋
435 - add up 29+28+27+....+2+1
2006-10-04 19:29:35
·
answer #5
·
answered by J 3
·
0⤊
0⤋
if you can talk to only one person at a time, then the answer is 15
2006-10-04 19:32:54
·
answer #6
·
answered by Anonymous
·
0⤊
0⤋