ind the standard equation of the circle that is tangent to both axes, center in the fourth quadrant, radius 8.

Answer 1

(x-8)^2 + (y+8)^2 = 64

Answer 2

The standard equation of a circle is:

(x-h)^2 + (y-k)^2 = r^2

Since you said it is in Quadrant IV and tangent, we know the center (h,k) will be at (8,-8).

So, we get:

(x-8)^2 + (y+8)^2 = 64

Regards,

Herkdrvr

Answer 3

(x-g)^2 + (y-h)^2 = R^2 you could fill in the constants by inspection. the middle ought to be 9 below the x axis and 9 to the desirable of the y axis so (g, h) = (9, - 9) (x - 9)^2 + (y + 9)^2 = 80 one