2006-10-04 11:50:58 · 5 answers · asked by Kenia V 1 in Science & Mathematics ➔ Mathematics
Let J be Joe's age now
Let L be Luis' age now
Write an equation for now:
J = 4L
Write an equation for 6 years from now:
(J + 6) = 2(L + 6)
Substitute 4L in for J:
4L + 6 = 2L + 12
Group like terms on opposite sides:
2L = 6
Divide both sides by 2:
L = 3
Now plug 3 into J = 4L
J = 4(3)
J = 12
So:
Joe is 12, Luis is 3
(and in six years they will be 18 and 9)
2006-10-04 11:53:56 · answer #1 · answered by Puzzling 7 · 0⤊ 0⤋
have L = Luis age and J = Joe's age
J = 4L
J + 6 = 2(L +6)
first plug the first value for J into the second equation:
J + 6 = 2(L +6)
4L + 6 = 2(L +6)
4L + 6 = 2L + 12
subtract 6 and 2L from both sides
2L = 6
L = 3
Luis is 3
plug this into the first equation to find Joe's age:
J = 4L
J = 4(3)
J = 12
Joe is 12
(in 6 years Joe will be 18 and Luis will be 9)
2006-10-04 19:01:10 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Joe is 12 years old and Luis is 3 and in 6 years Joe will be 18 and Luis will be 9 years old
2006-10-04 18:57:34 · answer #3 · answered by just anotha chick 4 · 0⤊ 0⤋
You should try doing your own homework.
2006-10-04 18:58:43 · answer #4 · answered by Fleecie 1 · 0⤊ 0⤋
i need to know
2006-10-04 18:52:15 · answer #5 · answered by surfergirl 5 · 0⤊ 0⤋