what are the oxidizing and reducing agents in these equations?

Question

(a) 2 MnO4-(aq) + 10 Cl-(aq) + 16H +(aq) 5 Cl2(g) + 2 Mn2+(aq) + 8 H2O(l)

Oxidizing agent:
Reducing agent:

(b) 8 H+(aq) + Cr2O72-(aq) + 3SO32-(aq) 2 Cr3+(aq) + 3 SO42-(aq) + 4 H2O(l)

Oxidizing agent:
Reducing agent:


6HCl(aq) + 2HNO3(aq) + 3Cu(s) 2NO(g) + 3CuCl2(aq) + 4H2O(l)

Oxidizing agent:
Reducing agent:

Answer 1

(a) Ox. agent: MnO4-, reduc.agent: Cl-. Because oxidation number of Mn decreases from +7 to +2 and the oxidation number of Cl increases from -1 to 0.

(b) Ox. agent: Cr2O7(2-), red. agent: SO3(2-). Because oxidation number of Cr decreases from +6 to +3 and the oxidation number of S increases from +4 to +6.


(c) Ox. agent: HNO3, reduc. agent: Cu. Because oxidation number of N decreases from +5 to +2 and the oxidation number of Cu increases from 0 to +2.

Answer 2

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