What is the area of a triangle that is 18 ft by 16 ft by 16 ft ?

Answer 1

First, recognize that you have an isosceles triangle, because two sides are identical.

Ok, then arrange the triangle so that the 18 ft side is your base; split the triangle in half, with a vertical line down the middle. Find the area of each half, and add 'em up.

The vertical line you've added is the height of each triangle, and each triangle's area is = 1/2 Base x Height.

The original base was 18 ft; and you've split it in half, so each half is 9 ft.

The height can be found using the Pythagorean Theorem,
x^2 + y^2 = r^2 where x and y are the two legs and r is the hypotenuse. So, solve for y, the height...

9^2 + y^2 = 16^2
81 + y^2 = 256
y^2 = 256 - 81 = 175
y = sqrt of 175 = 13.23 ft

So, back to area = 1/2 x base x height
area of each half = 1/2 x 9 ft * 13.23 ft = 59.54 ft

Area of the original triangle = 2 x 59.54 ft = 119.08 sq ft
Round it off to 119 sq ft.

Answer 2

165.22 ft^2

1/2 the base times the hieght. base = 18 ft
height = squareroot of (16^2 + 9^2) = sqrt(256 + 81) = 18.358 ft

so.....1/2 * 18 * 18.358 = 165.222 ft^2


18 is not the hypotenuse. dont listen to them. This is NOT a right triangle. squareroot(16^2 + 16^2)= 22.63. NOT 18.

Answer 3

4*16

Answer 4

this is a cool formula to calculate that...

area=sqrt(s(s-a)(s-b)(s-c))
where s=(a+b+c)/2 or perimeter/2.

s=(18+16+18)/2=26
area = sqrt(26 * (26 - 18) * (26 - 16) * (26 - 18)) = 128.996124

Answer 5

base times height divided by two equals area.
the hypotenuse is 18 and the two legs are 16...therefore
16x16=256....256/2=128
area equals 128 feet.

Answer 6

isnt it 0.5 x the base x the height?

Answer 7

(16x18)/2=144 square feet