3b + 11c - 4b - c = 3b - 4b + 11c - c
(regrouping to get like terms together)
3b - 4b = -b
11c - c = 10c
so: 3b + 11c - 4b -c = -b + 10c (or 10c - b)
2006-10-04 09:38:15
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answer #1
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answered by Dave_Stark 7
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Group like terms:
3b-4b+11c-c
Combine them:
(3-4)b+(11-1)c
you get
-b+10c
2006-10-04 09:37:22
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answer #2
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answered by James L 5
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3b - 4b = -b; 11c - c = 10c
Then, collecting terms, the answer is
10c - b (or -b + 10c)
2006-10-04 09:40:38
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answer #3
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answered by RG 4
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3b+11c-4b-c
= -b+10c
its simple
2006-10-04 09:38:43
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answer #4
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answered by R 3
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3b+11c-4b-c=3b-4b+11c-c=-b+10c=10c-b
I think i did it in the 4th garde
2006-10-04 09:43:33
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answer #5
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answered by yna_2006_cv 1
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3b+11c-4b-c
1: 3b-4b= -b
2: 11c-c= 10c
10c-b
2006-10-04 10:16:20
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answer #6
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answered by Anonymous
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3b+11c-4b-c
3b-4b+11c-c
-b+10c
2006-10-08 09:23:08
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answer #7
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answered by yupchagee 7
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put the like terms together 3b-4b=-1b
11c-c=10c
so it will be -1b+10c
2006-10-04 09:38:32
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answer #8
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answered by MISSREBEL 2
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those are in actuality a similar difficulty. in the 1st, ingredient out a three from the two numerator and denominator. 3x+6 = 3(x+2) 3x-6 = 3(x-2) Then the quotient = 3(x+2) / 3(x-2) = 3/3 * (x+2)/(x-2) = a million * (x+2)/(x-2) = (x+2)/(x-2) the 2nd works a similar way. you may desire to come to a decision what quantity to ingredient out.
2016-10-18 12:03:06
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answer #9
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answered by huegel 4
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It's called combining like terms. Combine the terms involoving b and combine the terms involving c. This will leave 2 terms, one with a b and one with a c. I don't do addition and subtraction here...
2006-10-04 09:40:53
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answer #10
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answered by Steve 7
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