In how many ways can 12 people be divided into hockey teams of 6 players each?
2006-10-04 09:18:50 · 6 answers · asked by ♥ 6 in Science & Mathematics ➔ Mathematics
12!/(6!*6!) = 924
2006-10-04 09:21:09 · answer #1 · answered by T 5 · 0⤊ 0⤋
Once you choose 6 people from the set of 12, to form one team, then the other team is determined as well.
Therefore, the number of ways is equal to the number of ways to choose 6 people from a set of 12, the binomial coefficient
C(12,6) = 12! / (6!6!).
2006-10-04 16:21:37 · answer #2 · answered by James L 5 · 0⤊ 0⤋
Only one way because there are six on a team. Plus your best skater has to be the goalie.
Cut out 12 pieces of paper, label them and go from there.
2006-10-04 16:22:16 · answer #3 · answered by tjc 2 · 0⤊ 0⤋
There are several notions but sometimes in text it is written as
"12 choose 6" = 12 ! / ( 6! (12-6)!)... you do know what n! means?
2006-10-04 16:26:09 · answer #4 · answered by rhino9joe 5 · 0⤊ 0⤋
each player could end up on either team... so 24 possibilities... I think
2006-10-04 16:23:22 · answer #5 · answered by simplyrelaxinginblvl 3 · 0⤊ 0⤋
By some mean.
2006-10-04 16:36:44 · answer #6 · answered by thewordofgodisjesus 5 · 0⤊ 0⤋