line has Y intersept (0,2) and is perpindicular to the line wiht 2x-3y=6
what is the equasion of the line? how?
2006-10-04 09:07:45 · 4 answers · asked by Ash1227 2 in Science & Mathematics ➔ Mathematics
We know the line is perpendicular to 2x-3y = 6, ehcih when written in standard form is y = (2/3)x - 2. This implies theat the gradient of our line is -1/(2/3) = -3/2.
Also we know a point on the line (0,2) so we can find the equaltion of our line from
y - y0 = m(x- x0)
y - 2 = (-3/2)(x - 0)
y = (-3/2)x + 2
2006-10-04 09:50:17 · answer #1 · answered by hackmaster_sk 3 · 0⤊ 0⤋
the first step that i always do is to put the equation in y-intercept form, which is y=mx+b, where m is your slope and b is the y-intercept. Therefore, your equation is y=-2/3x+-2. Now a line perpendicular to this line has to have the opposite slope, or "m", which in this case is a positive three halves. You said above that your y-intercept is (0,2), so "b" would be 2. Your perpindicular equation then comes out to be y=3/2x+2 or -3x+2y=6. Hope i helped :)
2006-10-04 09:18:08 · answer #2 · answered by smartass 3 · 0⤊ 0⤋
You need to determine the slope of the equation that is given. Then, use the fact that lines that are perpendicular have slopes that are negative reciprocals of each other to get the slope for your line. Once you do that, use your slope that you found and the y intercept to write the equation.
Answer: y = -3/2 x + 2
Be sure to do the work to check the answer I gave you.
2006-10-04 09:11:27 · answer #3 · answered by snebo87 2 · 0⤊ 0⤋
tricky task look on onto google this will help
2014-07-19 23:00:36 · answer #4 · answered by Anonymous · 0⤊ 0⤋