there is a snail at the bottom of a well and needes to get to the top, the well is 10 feet deep. By day the snail goes up 3 feet and by night it goes down 2 feet. how long will it take the sanil to get to the top.
2006-10-04 07:54:38 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
7 and 1/2 days. Every day it goes 1 foot so it would take 7 days to make it to the 7 ft. mark. on the 8th day, it would go three feet in the daytime, hence the seven and a HALF days.
2006-10-04 07:58:13 · answer #1 · answered by Casey 3 · 0⤊ 0⤋
10 Days.
2006-10-04 15:10:43 · answer #2 · answered by Sujal P 1 · 0⤊ 0⤋
He will reach the top at the end of the eighth day. The first 7 days, he goes the net of 1 foot up each day, so he is at 7 feet. On the 8th day, he will travel the final 3 feet.
2006-10-04 14:57:21 · answer #3 · answered by Jim R 3 · 1⤊ 0⤋
10 days
2006-10-04 14:58:17 · answer #4 · answered by josh and mell h 2 · 0⤊ 2⤋
10 days
2006-10-04 14:57:40 · answer #5 · answered by jonnyspirit 2 · 0⤊ 2⤋
10 days
2006-10-04 14:56:58 · answer #6 · answered by MaL 2 · 0⤊ 2⤋
That means that each day it goes up one foot, so you would think 10 days,
BUT...
On the 8th day, he'll have only three foot to go, and by day he goes up three feet, which would put him over the top.
So, if "day" means 1/2 a day, i.e. 12 hrs, then
7 days, 12 hrs
Regards,
Herkdrvr
2006-10-04 15:00:00 · answer #7 · answered by mysstere 5 · 0⤊ 2⤋
8 Days!!!
2006-10-04 14:58:25 · answer #8 · answered by Teepy 2 · 0⤊ 0⤋
1 ft a day equals ten days
2006-10-04 14:58:11 · answer #9 · answered by Ralph4545 1 · 0⤊ 2⤋