A student reacted 1.44 g of titanium with chlorine to form 5.70 g of a chloride X?

Question

can u tell me how many moles of Ti and Cl atoms were reacted?

Answer 1

It is explicitly stated in the problem that 1.44 grams if Ti are reacted. Divide this amount by the molar mass of Ti to get the number of moles of Ti.

You are also given the mass of the final product (5.70 grams). You know that 1.44 of those grams is Titanium...so simply subtract out the mass of the Ti to get the mass of the Chlorine.
After you have the mass of the Chlorine, divide by the molar mass of Chlorine gas to get the number of moles of Cl2. Remember, Chlorine is a diatomic element, Chlorine gas is really Cl2, not just Cl.

You can find the molar masses of each of these elements using a periodic table such as this one,
http://www.webelements.com/index.html

Answer 2

Titanium Chlorine

Answer 3

Atomic mass of Ti equals Ar = 47.88 g/mol. So the number of moles of Ti that reacted is:

n = m/Ar = 1.44/47.88 = 0.03 mol

mass of Cl that reacted = mass of compound - mass of Ti = 5.70 - 1.44 = 4.26 g.

Atomic mass of Cl equals Ar = 35.45. So the number of moles of Cl atoms that reacted is:

n = m/Ar = 4.26/35.45 = 0.12 mol

So 0.03 moles of Ti atoms reacted with 0.12 mol of Cl atoms.

(If you want you can find the empirical formula of the compound: Divide each number of moles by the less, by 0.03 and you get that each Ti atom combines with 4 Cl atoms (0.12/0.03 = 4). So the empirical formula is (TiCl4)v.