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Among all collections, S, of positive integers whose sum is 28, what is the largest product that the integers in S can form?

2006-10-04 06:43:27 · 4 answers · asked by Sasha 2 in Science & Mathematics Mathematics

4 answers

2+3+4+5+6+8=28
2x3x4x5x6x8=5,460


if they have to be unique (otherwise 2^14)

2006-10-04 07:01:15 · answer #1 · answered by novangelis 7 · 0 0

in all collection, only integers exist. now we know that for any set of n integers, Arithmetic Mean of those integers >= geometric mean of those integers. let a1, a2....an be n such integers forming a collection in S
then we have (a1+a2+...+an)/n>=(a1.a2.a3....an)^1/n
given a1+a2+a3+...+an=28. let a1.a2.a3...an = x. we need to maximize x
we have x^1/n<=28/n that is x<=(28/n)^n for all n. maximum x means maximum right hand side. now if u have studied calculus, to maximize the RHS, take its derivative with respect to n and equate to 0 ie d((28/n)^n)/dn=0 and find n. to differenciate right hand side, take logarithms and then use product rule.

I have a feeling i went wrong sumwhere but im pretty much sure this is the right way to go about the solution
:)

2006-10-04 07:03:08 · answer #2 · answered by netsavvy_sashi 2 · 0 0

What is cerdit? Do you do ANY of your homework yourself?

2006-10-04 07:13:27 · answer #3 · answered by Anonymous · 0 0

Hi. s^s^s...

2006-10-04 06:45:56 · answer #4 · answered by Cirric 7 · 0 1

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