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The problem goes as follows:


A particle of mass 'm' moves along a circle of radius 'R' with a normal acceleration varying with time as a=k(t^2), where k is a constant. find the time dependence of the power developed by all the forces acting on the particle, and the mean value of this power averaged over the first 't' seconds of motion.


I've tried a lot but in vain. can anyone help me solve it? please explain how you solve this kind of problems. i'm a beginner to high school physics.

2006-10-04 04:39:45 · 4 answers · asked by Anonymous in Science & Mathematics Physics

4 answers

The normal (centripetal) acceleration of a particle moving along a circular path is always v^2/R where v is the instantaneous (tangential) speed:

a = v^2/R = kt^2

This gives you the value of v as a function of t, and therefore the kinetic energy:

T(t) = (1/2)mv^2 = (1/2)mkRt^2

The instantaneous power is the time derivative of energy:

P(t) = dT/dt = mkRt

The average power over the first t seconds is the energy at time t divided by the elapsed time t:

T(t)/t = (1/2)mkRt

2006-10-06 10:18:20 · answer #1 · answered by shimrod 4 · 0 0

Hi
1. Given data are
mass = M
Radius= r
Velocity = kt^2

Find
Acceleration = V/T
Force = M*A

2006-10-04 04:57:18 · answer #2 · answered by Jenny 1 · 0 0

Since Power= F vector dotted with V vector

and they are 2 orthogonal vectors. F towards center and V tangent at each point. !F!*!V!*Cos(90)=0 for Cosine of 90 degrees is zero.

PS: !F! and !V! stand for lengths of these vectors.

Power(t)=invariant of time= zero

2006-10-04 04:50:36 · answer #3 · answered by burakaltr 2 · 0 0

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2016-10-01 22:25:41 · answer #4 · answered by ? 4 · 0 0

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