the 1st eqn. is "2x+3y=6"
and the 2nd eqn. is 4x+6y=12
anyone knows how??
PLS. help!!
2006-10-04 02:33:14 · 10 answers · asked by vanessa b 1 in Science & Mathematics ➔ Mathematics
x and y intercept
2x + 3y = 6.- - - - - - - - -Equation 1
4x + 6y = 12- - - - - - - - Equation 2
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Solving for y intercept equation 1
x = 0
2x + 3y = 6
2(0) + 3y = 6
0 + 3y = 6
3y = 6
3y/3 = 6/3
y = 2
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Solving for x intercept equation 1
y = 0
2x + 3y = 6
2x + 3(0) = 6
2x + 0 = 6
2x = 6
2x/2 = 6/2
x = 3
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Solving for y intercept equation 2
x = 0
4x + 6y = 12
4(0) + 6y = 12
0 + 6y = 12
6y = 12
6y/6 = 12/6
y = 2
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Solving for x intercept equation 2
y = 0
4x + 6y = 12
4x + 6(0) = 12
4x + 0 = 12
4x = 12
4x/4 = 12/4
x = 3
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In equation 1 and 2 the x intercept are 3
in equation 1 and 2 the y intercept are 2
They are on the same line
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The solution set { 3, 2 } for both equations
2006-10-04 03:46:11 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
I dont know the x and y intercept but this looks like a simultaneous equation to me.
The second equation is two times the first one.
So,
2(2x+3y) = 2(6) = 4x+6y = 12
So 12 = 12
2006-10-04 03:43:43 · answer #2 · answered by Anonymous · 0⤊ 0⤋
The x-intercept is where y=0, so, using either equation, plug 0 in for y. Using the first, this give you 2x=6, divide by 2 to get x=3. The y-intercept is where x=0, so plugging 0 in for x gives 3y=6. Divide by 3, y=2. Not sure if this is what you're going for...good luck!
2006-10-04 02:48:53 · answer #3 · answered by Anonymous · 0⤊ 0⤋
I'm not sure what you mean by solving using the x and y intercept.. These two equations describe the same line. You can tell because if you multiply the first equation by -2 and add it to the second equation you'll get 0=0.
When both variables drop out and you have a true statement left at the end, there are infinitely many solutions and the two equations will draw a single line.
2006-10-04 02:39:05 · answer #4 · answered by PatsyBee 4 · 0⤊ 0⤋
The 2nd equation is just the 1st equation multiplied by 2. So I think it's the same line.
If you solve for y in the 1st equation and substitute it into the 2nd equation, you'll see that 12=12.
2006-10-04 02:42:52 · answer #5 · answered by Clappuh 2 · 0⤊ 0⤋
2x+3y=6
4x+6y=12
both the equations are same and they are equation of same line.
If it intercept x -axis then y=0 and put the value of y in any equation,you will get x=3
If it intercept y -axis then x=0 and put the value of x in any equation,you will get y=2
Hence the line intercept at two point namely (3,0) and (0,2)
2006-10-04 03:18:38 · answer #6 · answered by dudul 2 · 0⤊ 0⤋
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2016-10-18 11:30:48 · answer #7 · answered by ? 4 · 0⤊ 0⤋
Is it two different questions? do you want to solve them simultaneously? it so you can't because they are the same. to find the x and y intercept for both individually you make the x=0 or the y=0
eg. to find the x-intercept, make y=0 and visa versa
2x+3y=6
2x+3(0)=6
2x=6
x=3
do the same for the rest!
2006-10-04 02:45:05 · answer #8 · answered by shynryd 2 · 0⤊ 0⤋
2x+3y=6
4x+6y=12 ...........divide the eq. by 2.
we have,
2x+3y=6
2x=6-3y..........................(1)
place this value in 2x+3y=6
2x+3y=6
6-3y+3y=6
6=6
6-6=0.
x,y have the any value,(0,2),(3,0)....................
2006-10-04 02:51:31 · answer #9 · answered by Anonymous · 0⤊ 0⤋
LOOKS LIKE A SIMULATANEOUS EQUATION
2006-10-04 02:43:04 · answer #10 · answered by CHAZ2006 3 · 0⤊ 0⤋