include some explanation on how u arrived at ur answer.
2006-10-04 01:02:11 · 6 answers · asked by smart_eluh 4 in Science & Mathematics ➔ Mathematics
Looks like I need some help on probability. have forgotten quite alot. mayb u can assist in this one too. Suppose 3 of a dozen oranges are bruised and 2 are chosen at random from the dozen. The probability that both are bruised i? include ur explanation plz
2006-10-04 01:08:51 · update #1
With the oranges, the probability both are bruised is 3/12 times 2/11. The numbers in the numerator represent the number of bruised oranges and those in the denominator, the total number to choose from. You have to multiply because for both to be bruised, you need both events to come true.
With the cards, the probability that they are not the same suit is 1 - 12/51, which will be just a hair different than 75% ... it isn't exactly 75% because you have already drawn one card, so that suit only has 12 cards left in the deck.
2006-10-04 01:13:17 · answer #1 · answered by metatron 4 · 1⤊ 1⤋
The playing cards aren't any more importnt; the shape of playing cards and the shape of matches are. the first card is drawn devoid of replace, making the shape of playing cards left = fifty one. because you drew some healthy, that signifies that you've only 12 playing cards of that healthy. so the probability of having yet another card of an same healthy is 12/fifty one; both truly a kind of are divisable by skill of three, so as it truly is (3 x 4)/(3 x 17), or 4/17. do not recognize the position to procure the different answer, in spite of the indisputable fact that it really is incorrect.
2016-11-26 02:08:15 · answer #2 · answered by kirtiman 3 · 0⤊ 0⤋
The 1st card can be anything.
then there are 51 cards left and 39 cards are not of the same suite
so probability = 39/51 (of a different suit) = 13/17
2006-10-04 01:42:27 · answer #3 · answered by Mein Hoon Na 7 · 2⤊ 0⤋
75%. After the first card is drawn; the probability the second card drawn is the same is 1 in 4. The probability the second card is different is 3 out of 4. Hope this makes sense.
2006-10-04 01:12:51 · answer #4 · answered by short5641sweet 3 · 0⤊ 2⤋
Suposing that you refer to a poker deck. 13 cards of each suit sum 52. So after we take the first card there are 52 cards left. The odds of the second one beeing the same suit as the first one are:
P = 12 / 52
2006-10-04 01:32:53 · answer #5 · answered by Uncle Rodri 1 · 0⤊ 2⤋
0.25
2006-10-04 01:10:53 · answer #6 · answered by Anonymous · 0⤊ 1⤋