Calculate the root mean square velocity for the O2 molecules in a sample of O2 gas at 25.0°C. (R = 8.3145 J/K · mol)
2006-10-03 20:23:15 · 5 answers · asked by jasmine m 1 in Science & Mathematics ➔ Chemistry
The formula for root mean square speed is
v(rms) = sqrt( 3kT/m )
Make sure you convert Celsius to Kelvin by adding 273. The mass of O2 you can find in the back of your book along with the periodic table of elements.
Just plug in the values, sqrt( 3 * 1.38x10^-23 * 290 / 32 )
=1.96x10^-11 m/s
2006-10-03 20:36:27 · answer #1 · answered by bloop87 4 · 1⤊ 4⤋
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Calculate the root mean square velocity for the O2 molecules in a sample of O2 gas at 25.0°C. (R = 8.3145 J/K
Calculate the root mean square velocity for the O2 molecules in a sample of O2 gas at 25.0°C. (R = 8.3145 J/K · mol)
2015-08-13 14:56:23 · answer #2 · answered by Anonymous · 0⤊ 3⤋
Root Mean Velocity
2016-12-14 19:47:40 · answer #3 · answered by ? 4 · 0⤊ 1⤋
bloop87 is right - except that m in the formula is the mass of one molecule, not the molar mass - but we can express the same formula as:
Vrms = sqrt(3RT/Mr) where Mr is the molar mass in kg/mol, T the temperature in Kelvin and R = 8.3145 J/K the universal constant.So:
Vrms = sqrt(3*8.3145*298/0.032) = 482 m/s
2006-10-03 23:59:43 · answer #4 · answered by Dimos F 4 · 6⤊ 0⤋
I would like to ask the same question as the op.
2016-08-23 08:07:45 · answer #5 · answered by Anonymous · 0⤊ 2⤋
This was bugging me too
2016-08-08 16:25:53 · answer #6 · answered by Anonymous · 0⤊ 2⤋
rms=((3R(25+273))/0.032)^(.5)=482
2006-10-03 20:34:40 · answer #7 · answered by NCH 2 · 4⤊ 0⤋