two numbers differ by 25. three times the smaller is 9 less than twice the larger. find numbers.
2006-10-03 17:34:54 · 4 answers · asked by m 1 in Science & Mathematics ➔ Mathematics
Translate:
j - k = 25
3k = 2j - 9
Simplify:
j = 25 +k
Substitute:
3k = 2(25 +k) - 9
Simplify:
3k = 41 +2k
k = 41, and therefore j = 66
2006-10-03 17:40:52 · answer #1 · answered by Anonymous · 1⤊ 0⤋
So, translate the words into math:
two numbers differ by 25. --> L - S = 25
three times the smaller is 9 less than twice the larger. find numbers. --> 3S = 2L - 9
2006-10-04 00:39:23 · answer #2 · answered by arbiter007 6 · 0⤊ 0⤋
j - k = 25
3k = 2j - 9
j = 25 +k
so
3k = 2(25 +k) - 9
3k = 41 +2k
k = 41, j = 66
2006-10-04 01:10:35 · answer #3 · answered by locuaz 7 · 0⤊ 0⤋
let x be the smaller number
let y be the larger number
your first equation is:
y-x=25
your second equation is:
3x=2y-9
in the 1st equation:
y=x+25
substitute to the second equation:
3x=2(x+25)-9
3x=2x+50-9
3x-2x=41
x=41
solve for y:
y-x=25
y-41=25
y=41+25
y=66
2006-10-05 10:13:18 · answer #4 · answered by yolly jr f 1 · 0⤊ 0⤋