standing at the edge of a seaside cliff kicks a stone over the edge with a speed of vi = 17 m/s. The cliff is h = 52 m above the water's surface.
(a) How long does it take for the stone to fall to the water? ___s
(b) With what speed does it strike the water?___m/s
2006-10-03 17:24:13 · 3 answers · asked by tingerpoo 2 in Science & Mathematics ➔ Physics
Assuming your initial velocity is downward then; h-vi*t-(1/2)gt^2=0
Input your initial velocity and g=9.8 m/s^2 and h-52 m
(a) Solve for zeros, only the positive one means anything t=1.956 seconds.
(b)then for velocity at time=1.956 V(final)=vi+gt, Vf=36.17
2006-10-03 17:42:11 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Seems to always be windy at the beach. So to answer correctly a person would have to know what direction the wind is coming from and at what speed. Example.. If you were on the west coast and there was a strong westerly.. lets say 40 knots.. the wind would hit the cliff go in an up word direction and slow your rock down dramatically..
2006-10-03 17:41:20 · answer #2 · answered by mr.longshot 6 · 0⤊ 0⤋
not sure but the bigger the rock the bigger the splash
2006-10-03 17:29:47 · answer #3 · answered by fragle2c 5 · 0⤊ 0⤋