a page of a school yearbook is 8 1/2 in. by 11 in. The left and right margins are 1 in. and 2 1/2 in. respectively. The space between pictures is 1/4 in. How wide can each picture be to fit across the width of the page? i need a verbal model for this problem please.
2006-10-03 17:06:15 · 4 answers · asked by NABEELiOS 1 in Science & Mathematics ➔ Mathematics
Insufficient information...
Missing information is how many pictures do you need to be on a page or more specifically how many rows and columns.
2006-10-03 17:15:31 · answer #1 · answered by feanor 7 · 0⤊ 0⤋
The working width of the page is 8.5" - 1" - 2.5" = 5"
You can subtract 1/4" from the left margin, increase your working width of the page to 4.75" and make the generalization that each photo is w"+1/4" wide. Now N * (w"+.25") - 4.75" = 0, and each value of N = Number of photos across the page from 1 to [MAX], will yield a new width for those photos.
2006-10-03 17:20:56 · answer #2 · answered by sheramcgyver 2 · 0⤊ 0⤋
The space available is the width less the margins less the 1/4 in.
I can't tell you anything about the INDIVIDUAL picture widths, only that the SUM of their widths can't exceed the calculation above. If they are each the same width, then divide the calculation above by 2 and you have an answer.
2006-10-03 17:14:19 · answer #3 · answered by Steve 7 · 0⤊ 0⤋
you only need the width of the page, so..
i change fractions to decimals first..
8.5in - 2.5in - 1in = 5in
if you only need to fit 2 pictures across the page, divide 5in to 2 and subtract 0.25in..
my answer is 2.25 or 2 1/4in wide..
2006-10-03 17:26:57 · answer #4 · answered by lyra_may 2 · 0⤊ 0⤋