n + 2
2006-10-03 16:56:52
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answer #1
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answered by Sam 3
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102 and 104 are the numbers.
You can write the smaller number as n.
Since the larger number is a consecutive even integer, it can be written as n+2.
When you add them together, you get 206, which is represented by:
(n) + (n+2) = 206
2n + 2 = 206
Solve for n
2n = 204
n = 102
Since n = 102, then n+2 = 104. Those are your two numbers.
2006-10-03 16:56:11
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answer #2
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answered by Rev Kev 5
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n+2. Then, n+n+2 = 206; n = 102.
2006-10-03 16:59:37
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answer #3
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answered by Anonymous
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102 and 104.
n + y = 206
y = 206 - n
n < y
2006-10-03 16:59:47
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answer #4
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answered by MnM 2
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102 and 104
or
n+(n+2)=206
2n+2=206
2n=206-2
2n=204
n=204/2
n=102
so
102+(102+2)=206
2006-10-03 16:59:04
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answer #5
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answered by Mike 1
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If the first number was 10, the next CONSECUTIVE EVEN NUMBER would be 12, right? If the first number was 132, the next CONSECUTIVE EVEN NUMBER would be 134. So if the first number is "n", the next CONSECUTIVE EVEN NUMER would be...?
2006-10-03 16:59:28
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answer #6
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answered by wuxxler 5
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102&104
2006-10-03 17:02:37
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answer #7
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answered by khizra64 1
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Think about it -- If N equals the first even number, what do you need to add to N to get another even number?
Think about it this way -- If 2 is an even number, what do you add to it to get the next even number?
2006-10-03 16:58:21
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answer #8
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answered by Anonymous
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n+(n+2)=206 Work it, it is easy, now.
2006-10-03 16:58:05
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answer #9
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answered by Anonymous
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103?
2006-10-03 16:54:42
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answer #10
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answered by happydawg 6
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