I have a problem that I am needing help with as soon as possible...I'm trying to find the derivitive of 3(3^1/2)...if you actually know...please help me out. It's due tomorrow, and I have to get it done tonight!
2006-10-03 16:23:29 · 10 answers · asked by fanciergirl2002 1 in Science & Mathematics ➔ Mathematics
I can tell you this about Calculus, it is really hard.
2006-10-03 16:30:53 · answer #1 · answered by Anonymous · 0⤊ 3⤋
the 1/2 should be brought down in front and is treated as a coefficient The 1/2 will be replaced with ((1/2)-1), which is -1/2. That's all I can do because there is no variable to take derivitive.
2006-10-03 16:35:38 · answer #2 · answered by dantrc724 4 · 0⤊ 0⤋
Yep. The derivative of 3(3^1/2) is 0. The derivative of any number is 0. Unless you meant 3(x^1/2) which in that case it would be 3/2 * x^(-1/2)
2006-10-03 16:35:13 · answer #3 · answered by Anonymous · 0⤊ 0⤋
3(3^(1/2)) is a constant. The derivative of a constant in always 0.
2006-10-04 04:09:39 · answer #4 · answered by Math_Guru 2 · 0⤊ 0⤋
Sure. The derivative is zero. 3(3^1/2) is a constant, and the derivative of any constant is zero.
2006-10-03 16:28:53 · answer #5 · answered by Pascal 7 · 2⤊ 0⤋
I'm afraid you'll need to clarify. Is there a variable in there?
Because, if not, then you are asking for the derivative of ~5.1.
That is a constant, and the derivative of a constant is always 0.
2006-10-03 16:30:18 · answer #6 · answered by Rev Kev 5 · 0⤊ 0⤋
The derivative of a constant is always zero. To prove this, use limit (as h approaches zero) of {f(x+h) - f(x)}/h, and plug in your x value. This is called the difference quotient.
2006-10-03 17:58:55 · answer #7 · answered by trumanity 2 · 0⤊ 0⤋
calculus is easy and is very knowledgeable. if it is easy for you now it will help you in later days.
2006-10-03 16:27:03 · answer #8 · answered by sharon s 1 · 0⤊ 0⤋
kinda confused, cuz you don't have a variable to take the derivative of. Please clarify so i can help
2006-10-03 16:25:41 · answer #9 · answered by JSAM 5 · 0⤊ 0⤋
no sorry.....
2006-10-03 16:25:03 · answer #10 · answered by Anonymous · 0⤊ 0⤋