...three equilateral triangles inside an octagon?
2006-10-03 14:28:24 · 5 answers · asked by Heckel 3 in Science & Mathematics ➔ Mathematics
Oh yeah - the octagon is already drawn for you, so what we are after is how many lines INSIDE the octagon to create three equilateral triangles.
2006-10-03 14:57:00 · update #1
So the octagon needs 8 lines itself, or are you not counting that.
For the triangle, you'd need at least another 3 lines, but I don't know how I would show that to you using text.
http://www.yourdictionary.com/images/ahd/jpg/A4octago.jpg
Take that octagon, first.
Label the topmost point on the left A, and go all the way around clockwise, labelling each point the next letter.
Draw a line from H to C. Now draw a line from A to the center of HC. Draw another line from B to HC. You should have 3 equilateral triangles.
2006-10-03 14:35:08 · answer #1 · answered by Manan T 3 · 0⤊ 0⤋
17 i believe, 8 for the octogone, 3 for the first equ., 3 for the 2nd, and 3 for the 3rd which in numerical form, 8+ 3*3= 17
2006-10-03 21:43:36 · answer #2 · answered by hotchikdancer 2 · 0⤊ 0⤋
one
2006-10-03 21:32:28 · answer #3 · answered by Mysterious 4 · 0⤊ 0⤋
three: two long (like a diameter) and one short (like a radius)
2006-10-03 22:10:10 · answer #4 · answered by Kassi C 2 · 0⤊ 0⤋
5 I think could be wrong
2006-10-03 21:30:46 · answer #5 · answered by musicovermind 1 · 0⤊ 0⤋