English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

During a throw, a baseball pitcher exerts a force of 3.20 m before releasing it. If the 0.12-kg ball leaves the pitcher's hand with a speed of 35.0 m/s, how much of a force did the pitcher exert on the ball?

2006-10-03 13:20:25 · 4 answers · asked by Bao Wow 3 in Education & Reference Homework Help

During a throw, a baseball pitcher exerts a force of on the ball 3.2 m before releasing it. If the 0.12-kg ball leaves the pitcher's hand with a speed of 35.0 m/s, how much of a force did the pitcher exert on the ball?

2006-10-03 13:26:37 · update #1

sorry i mistyped the info on the first part

2006-10-03 13:27:08 · update #2

During a throw, a baseball pitcher exerts a force on the ball though a distance of 3.2 m before releasing it. If the 0.12-kg ball leaves the pitcher's hand with a speed of 35.0 m/s, how much of a force did the pitcher exert on the ball?

sorry the question was mistyped


FINAL CORRECTION

2006-10-03 13:28:55 · update #3

4 answers

You can do this with Newton's second law or with impulse. I'm going to assume you want the first.

Think about what you know. You know the distance over which the ball was accelerated, you know the final and initial velocities of the ball, and you know its mass. Since all you'll be able to calculate is the average force anyway, just assume it to be constant. If the force is constant, then the acceleration is constant, so you can find the average velocity of the ball:

v(avg) = (v0 + vf)/2 = 17.5 m/s

Given the distance, then, you can find the time it took:

v(avg) = s/t

t = s/v(avg) = 3.20 m/17.5 m/s = .183 s

Now, you can determine the acceleration by using the definition for average acceleration:

a = (vf - v0)/t = (35.0 m/s - 0)/.183 s

a = 191 m/s^2

Now get the force:

F = ma = .12 kg (191 m/s^2) = 23 N (to two significant digits)

Do you understand why your final answer has only two s.d.s?

Edit: "The GUY below", hmm? Clearly, I have to change my avatar...

2006-10-03 13:35:28 · answer #1 · answered by Anonymous · 0 0

"a force on the ball though a distance of 3.2 m before releasing it"

That doesn't make much sense. What's the "though" supposed to mean and how can he throw it 3.2 meters before releasing it? He'd have to run with it that distance or stretch that far.

Check your problem again.

2006-10-03 20:39:01 · answer #2 · answered by gabyrig 3 · 0 0

how much force did the pitcher exert, or how much work was done?

The guy below is correct if you're looking for force and not work (force over a distance)

2006-10-03 20:24:21 · answer #3 · answered by Eric 2 · 0 0

Comparable to a forced pitch.

2006-10-03 20:28:21 · answer #4 · answered by Anonymous · 0 0

fedest.com, questions and answers