15 .... 4
---- ÷ ----
2 ....... 7
Just invert and multiply:
15 .... 7
---- x ----
2 ....... 4
105
-----
. 8
Convert to a mixed fraction:
= 13 1/8
2006-10-03 12:21:15
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answer #1
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answered by Puzzling 7
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15/2 divided by 4/7
first you need the reciprical of 4/7 which is 7/4. also turn the diviion sign into a multiplication sign.
15/2 X 7/4
15 X 7 is 105 and 2 X 4 is 8 so its 105/8
I don't think you can simplify, but if you need to make it a mixed number its 13 1/8 as a decimal its 13.125
2006-10-03 12:23:25
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answer #2
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answered by Kertcralwer 2
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instead of dividing 2 fractions swap the top and bottom numbers of one fraction over then multiply by the other fraction
eg. 15/2 * 7/4 or 2/15 * 4/7
so your answer is 105/8
2006-10-03 12:24:52
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answer #3
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answered by Anonymous
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15/2 divided by 4/7
that is the same as:
15/2 * 7/4
= 105/8
2006-10-03 12:22:26
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answer #4
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answered by vabanu 2
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15/2 divided by 4/7 you have to flip 4/7 to 7/4 and multiply 15/2 and 7/4 and you will get 105/8
2006-10-03 12:54:06
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answer #5
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answered by Anonymous
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Yes recipricate the 2nd fraction, then multiply and simplfy.
15/2 * 7/4 = 105/8 = 13.125 or 13 and 1/8
2006-10-03 12:31:54
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answer #6
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answered by rogueryche 3
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15/2 divided by 4/7
15/2 times 7/4
105/8 (the top numbers times the bottom ones)
13.125
2006-10-03 12:21:50
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answer #7
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answered by Sylvie M 3
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Yes. You need to recipricate the second number and change division to multiplication. It should be like this:
15/2 X 7/4
2006-10-03 12:20:47
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answer #8
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answered by Oklahoman 6
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yes invert the 4 over 7 and multiply the two so it becomes 15/2 multiply by 7/4
2006-10-03 12:22:41
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answer #9
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answered by macks2u 2
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(15/2)/(4/7) = (15/2)(7/4)
The reason we multiply the upper fraction by the reciprocal of the lower fraction is shown as follows:
(a/b)/(c/d)
The lower fraction becomes 1 if I multiply it by d/c (its reciprocal
(c/d)(d/c) = 1
Whatever is done to the lower fraction must be done to the upper fraction as well
(a/b)/(c/d) = [(a/b)(d/c)]/[(c/d)(d/c)] = [ad/bc]/[1] = ad/bc
2006-10-03 12:30:21
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answer #10
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answered by Anonymous
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