The product of two consecutive odd integers is 195.?

Question

please show the equation and the answers

Answer 1

13,15

um...
x*(x+2) = 195
x^2+2x = 195
x^2+2x-195=0
(x-13)(x+15)=0
x = 13, -15

either 13 and 15, or -15 and -13. You don't count negatives, so yeah.

Answer 2

x ( x + 2 ) = 195
x^2 + 2x = 195
x^2 +2x - 195 = 0

Quadratric equation or factor to solve for x.
(x + 15)(x - 13) = 0

x = -15 or 13

so your answers are:
13 x 15 = 195
-13 x -15 = 195

Note, a much easier way to do this is to take the sqrt(195) and realize that the answer is going to have to be the odd numbers on either side.

Answer 3

okay, so two consecutvie odd integers are 2 numbers apart, right? so your two nubmers are
x and (x+2)

Their product is 195, so now set them equal to 195.

x(x+2) = 195.
x^2 + 2x = 195.
x^2 + 2x - 195 = 0
x^2 + 15x - 13x - 195 = 0
x(x + 15) - 13 (x + 15) = 0
(x - 13) (x + 15) = 0
so x = 13 or x = -15

Plug these back in your numbers, you get the numbers as:

13 and 15
or
-15 and -13

Answer 4

n(n+2)=195
n^2 + 2n -195=0
(n + 15)(n - 13)=0
n= -15 or n=13

(-15)(-13) = (13)(15)= 195